The guidelines provided in the
solution to Problem #110 notwithstanding, Problem of the Week #111 presents a case where breaking the prime is probably best. As things stand, Black's cubeless chances are only around 42% (see
http://www.bkgm.com/rgb/rgb.cgi?view+1543), and they will be less if he cannot achieve an optimal close out. Yet, there they are: two juicy blots in White's home board, just waiting to be hit. If Black can get one of them, he will become the favorite.
Hitting gives Black two advantages. When White hits the return shot from the bar, Black may well get another direct shot at one or two blots. And when White misses, Black will have stolen a tempo from White, making it much less likely that White will be able to clean up his blots.
Also, note the duplication. The ones and twos that White needs to clean up his board are two of the three numbers he can use to enter from the bar. Unless he rolls 11, 22, 31 or 32, any other one or two that he rolls will not allow him to enter and simultaneously clean up his blots.
By playing bar/21, 8/3*, Black can preserve a four-point block. Playing bar/20, 7/3* is distinctly inferior.
My solution:
bar/21, 8/3*
For the Record
I am so often wrong that I like to post my record in these messages. It's kind of a truth-in-advertising thing.
Grunch: I have been answering these problems without the use of a bot, and before checking the excellent solutions of others, since Problem 28. My record at this writing is 49%.
Last edited by Taper_Mike; 07-03-2011 at 12:52 AM.