Join Date: Dec 2009
Posts: 54
In a sample of 10.4 million hands, Poker Stove tells me that
QQ vs A "Random" hand
has the following probabilities:
79.63% vs 19.8% and 0.57% the tie
I am assuming that Pokerstove puts QQ in one side of the equation, picks a random hand in the other side, deals out a board of 5 cards and counts who won the showdown. And does this 10.4million times.
But here is my question. There are 169 starting hands. As we know there are 4 ways of getting AK suited but 12 ways of getting AK offsuit. If you take suits into account then there are 1326 starting hands. Does the random hand that poker Stove selects correctly follow the distribution of the starting hands population?
If Pokerstove selects one of the 169 starting hands with equal probability, then we wouldn't get the same answer that we would when it selects the random hand in the same proportions as you get in 1326 starting hands.
So can anyone tell me, is each random hand selected on a 1/169th basis or is it selected on the basis that there are 6/1326ths ways to get AA, 12/1326ths ways to get Ako and 4/1326ths ways to get AKS? (which to my mind would be correct). Apologies if any of this is unclear.
And finally, without wishing to sound too probing how do you actually know this for a fact?
