Random question...at a full ring poker table, what’s the chances that the players directly to your left and right share one of your whole cards? For example...I’m in seat 5 and my hand is Q10 offsuit. How often or what percentage of the time will seat 4 OR seat 6 have either a Q or a 10? What’s the equation to quantify this?
When you have a pocket pair, there is ~84.5% chance that none of your neighbours' 4 cards will be either of the 2 out of 50 that are same rank as your hole cards.
When you have a non-pair, there is a ~58.9% chance that none of the your neighbours' 4 cards will be any of the 6 out of the 50 that are the same ranks as your hole cards.
You get a pocket pair ~5.9% of the time, unpaired ~94.1% of the time.
(5.9% x 84.5%) + (94.1% x 58.9%) = 60.4% chance of missing
