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Basic Swapping Question

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06-29-2017 , 12:09 AM

Equilibria

stranger

Join Date: Nov 2014 Posts: 8

Let's say that two players agree to swap 10% in a $1,000 buyin tournament. Player 1 busts for $0 and Player 2 wins $10,000. Should Player 1 receive $1000 (.1 x 10,000) or should he receive $900 (.1 x (10,000-1,000))? Obviously it doesn't really matter how they do it as long as they've agreed, but say they forgot to specify how it would be done. Which way is most typical?

Last edited by Equilibria; 06-29-2017 at 12:14 AM.

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06-29-2017 , 12:43 AM

U shove i call

Pooh-Bah

Join Date: Nov 2008 Posts: 3,809

$1000 buyin isn't factored in.

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06-29-2017 , 01:53 AM

TheChamp11

Carpal \'Tunnel

Join Date: Jun 2010 Posts: 6,953

Total cash

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07-08-2017 , 11:26 AM

Yoshi63

old hand

Join Date: Jan 2007 Posts: 1,940

You can look at it two ways:

Player 1 receives 10,000 x 10% = 1,000 for the total cash
Player 2 receives 0 x 10% = 0

Or

Player 1 receives 9,000 x 10%= 900 for the net profit
Player 2 owes 1000 x 10% = 100 for Player 1's net loss

Either way Player 1 receives $1000

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07-09-2017 , 06:22 AM

TreadLightly

Pooh-Bah

Join Date: Oct 2013 Posts: 3,709

Quote:

Originally Posted by TheChamp11

Total cash

this

you swap 10% of a 1k, that player cashes for $10k , you do not cash ($0)

$10k + $0 = $10k / 10%= $1k owed to you

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