Some interesting math that I will prolly mes up since I haven't done anything like this in a long time:
Assumption: If we b/f, we always have the worst hand when villain raises.
b = percent of the time villain bets when checked to with a worse hand
c = percent of the time villain calls a worse hand when we bet
-10 = pot size after villain bets riv
The equation for the EV of c/f should be:
f(b) = b * -10 + (1-b) * 0
The equation for the EV of b/f should be:
f(c) = c - (1-c)
So using a graphing calculator, I came up with the following values. The values can be interpreted as "B/f is better than c/f if villain bets a worse hand > b% of the time given c".
c = 10%, b = 8%
c = 20%, b = 6%
c = 30%, b = 4%
c = 40%, b = 2%
c = 50%, b = 0% (we should obviously always bet if we are winning > 50% of the time when called)
The takeaway from this is that we have to be more and more confident in our read the more we expect villain to call a worse hand when we bet when comparing b/f and c/f.
So if we think villain will call with stuff like 44 and 22 and 76s, b/f is almost certainly better since we will win close to 40% of the time when he calls. Villain would only need to bet a worse hand > 2% of the time when we check in this case for c/f to be a bad. If he does so even 3-4% of the time, it is a disaster for us.
I do think he will fold 44 and 22 though, so we are probably safe since he would need to bet a worse hand 6-8% of the time which seems silly to me given the read.
Just imagine how complex things can get if we consider the possibility of a bluff raise... in fact, a river bluff raising range starts making c/c and b/c real possibilities at certain thresholds. And big bet tards say LHE is solved