checktheriver -
Thanks for the reply. Sadly I do not understand your hint, but I have come upon a simpler way of showing the existence of such a g(x). Assume g(x) is in the space spanned by {1,x,...,x
N}. Then we have
So that
Now our conditions for l=0,1,...,N imply the system of N+1 equations
And the coefficient matrix here is a
Hilbert matrix, hence invertible. Thus we can solve for the coefficients of g(x).
But this is not actually my homework problem. My homework is this: let P
N be the space of real polynomials of degree ≤ N, taken as a subspace of L
∞([0,1]). Define a bounded linear functional δ on P
N by:
Now by the Hahn-Banach theorem, δ extends to a bounded linear functional Δ on all of L
∞([0,1]) with the same norm.
Question: is it possible to find a fixed g(x) ∈ L
1([0,1]) so that it holds...
...for all f(x) ∈ L
∞([0,1])?
Ok, so evidently the g(x) we found above, which satisfies the condition ∫
[0,1]x
kg(x)dx = δ
k1, yields a bounded linear functional Φ
g on L
∞([0,1]) so that:
But...does this tell us anything about Δ? (God, fml I'm incompetent.)