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| Science, Math, and Philosophy Discussions regarding science, math, and/or philosophy. |
10-26-2011, 07:24 PM
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#1981
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grinder
Join Date: Dec 2006
Posts: 420
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Re: The Official Math/Physics/Whatever Homework questions thread
Quote:
Originally Posted by checktheriver
The computation is correct, P(A|B^c)=1/2.
However, what we are really interested in is P(A|Bg) (and P(A|Cg) ), where Bg is the event "the guard tells him B will be set free" (resp. Cg for C).
Notice that these events are not the same : Bg is always a subset of B^c (same for C), but you cannot have both Bg=B^c and Cg=C^c, because on the intersection of B^c and C^c (i.e. A), the guard must choose between saying B or C.
The probabilities P(A|Bg) and P(A|Cg) will depend on the guard's "strategy", i.e. what he says when both B and C will be set free.
For instance, you can try to show that :
- if he picks 50% B or C, then P(A|Bg)=P(A|Cg)=1/3,
- if he picks B, then P(A|Bg)=1/2 and P(A|Cg)=0.
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My answer was writtin thinking they were the same, B^c was the event "the guard tells him B will be set free". Its been a while since ive done anything to do with sets and Id forgotten that ^c was common notation for complements.
Also I should have been clearer that I was assuming the guard's "strategy" was to show no preference to picking B or C. Perhaps this was unjustified, but it seemed trivially obvious that a guard with a bias giving you information is going to affect the probability of your own execution.
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10-27-2011, 12:19 AM
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#1982
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journeyman
Join Date: Aug 2007
Posts: 272
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Re: "Monty Hall" style problem
Quote:
Originally Posted by WAtR
Here is the problem:
Quote:
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Three prisoners are informed by their jailer that one of them has been chosen at random to be executed and the other two are to be freed. Prisoner A asks the jailer to tell him privately which of his fellow prisoners will be set free, claiming that there would be no harm in divulging this information because he already knows that at least one of the two will go free. The jailer refuses to answer this question, pointing out that if A knew which of his fellow prisoners were to be set free, then his own probability of being executed would rise from 1/3 to 1/2 because he would then be one of two prisoners. What do you think of the jailer's reasoning?
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This sounds a lot like my favorite variant of the Monty Hall problem, which has the same setup as usual with the one caveat that Monty forgot to take his medication and can't remember which door has the prize behind it. So you pick Door A. In desperation, he flips Door B to reveal... nothing! Mopping sweat from his brow, he then asks whether or not you'd like to switch. Should you?
It's kind of fun to pose this question to people who have just grasped the solution to the original version of the problem. They never get it right.
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10-27-2011, 03:59 PM
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#1983
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old hand
Join Date: Mar 2009
Location: Yes
Posts: 1,332
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Mathematical Proof
f : X → Y is injective if and only if, given any functions g, h : U → X, whenever f ∘ g = f ∘ h, then g = h
Again, I need to prove the above. I've been looking for a few hours now w/o success 
Someone please help me out.
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10-27-2011, 05:47 PM
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#1984
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adept
Join Date: Jul 2008
Location: Oh **** I'm dead !!
Posts: 955
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Re: Mathematical Proof
Isn't that just an extended definition ?
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10-27-2011, 06:14 PM
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#1985
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Carpal \'Tunnel
Join Date: Sep 2004
Location: farther back
Posts: 6,604
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Re: Mathematical Proof
Should be in homework thread?
⇒ Fix g,h: U → X. Suppose that for some u ∈ U, we have f(g(u)) = f(h(u)). Because f is injective, g(u) = h(u). In particular, if f(g(u)) = f(h(u)) for all u ∈ U, then g ≡ h.
⇐ Suppose f(x 1) = f(x 2) for x 1, x 2 ∈ X. We now define two functions g,h: U → X. For all u ∈ U, g(u) = x1.
For all u ∈ U, h(u) = x2. Thus f(g(u)) = f(h(u)) for all all u ∈ U. By assumption, this requires g ≡ h; which means x 1 = x 2. This proves f is injective.
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10-27-2011, 07:44 PM
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#1986
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Pooh-Bah
Join Date: Aug 2006
Location: you got it
Posts: 4,008
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Re: Mathematical Proof
Quote:
Originally Posted by Dasq1306
Isn't that just an extended definition ?
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It's the categorical definition of an injective morphism (no points/elements involved, just other morphisms).
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10-28-2011, 01:15 PM
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#1987
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old hand
Join Date: Mar 2009
Location: Yes
Posts: 1,332
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Re: The Official Math/Physics/Whatever Homework questions thread
Great, thanks for the responses
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10-30-2011, 03:56 PM
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#1988
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Pooh-Bah
Join Date: May 2005
Posts: 5,653
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Re: The Official Math/Physics/Whatever Homework questions thread
really not quite a homework problem but...
I'm in engineering and taking cal II, doing ok in the class, but I feel like any of the conceptual advanced applied questions I don't have a good sense of how to relate/put it into a mathematical formulation.
any tips on how to make it relevant? or how to learn to better apply it to problem solving?
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11-03-2011, 09:47 PM
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#1989
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veteran
Join Date: Jan 2007
Location: PDX Oregon
Posts: 2,466
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Re: The Official Math/Physics/Whatever Homework questions thread
Can someone remind me how to factor this kind of trinomial ?
x^2-xy-30y^2
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11-03-2011, 10:06 PM
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#1990
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banned
Join Date: Feb 2007
Posts: 17,356
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Re: Mathematical Proof
Quote:
Originally Posted by lastcardcharlie
It's the categorical definition of an injective morphism (no points/elements involved, just other morphisms).
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More precisely, of a monomorphism. In Sets, these would be the injective functions. (Injective has a different meaning in other settings; in particular it refers to having an extension property w.r.t. monomorphisms.)
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11-03-2011, 10:11 PM
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#1991
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Carpal \'Tunnel
Join Date: Mar 2007
Location: Redoubling with gusto
Posts: 10,706
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Quote:
Originally Posted by Acemanhattan
Can someone remind me how to factor this kind of trinomial ?
x^2-xy-30y^2
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same idea as factoring a quadratic in one variable.
how do you factor x^2 - x - 30?
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11-03-2011, 10:21 PM
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#1992
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veteran
Join Date: Jan 2007
Location: PDX Oregon
Posts: 2,466
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Re: The Official Math/Physics/Whatever Homework questions thread
Quote:
Originally Posted by Wyman
same idea as factoring a quadratic in one variable.
how do you factor x^2 - x - 30?
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(x-6) (x+5) i believe
I see now. Thanks
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11-04-2011, 01:24 PM
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#1993
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grinder
Join Date: Dec 2010
Location: T.Dot
Posts: 493
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Re: The Official Math/Physics/Whatever Homework questions thread
Expected Value question:
The normal weekly demand of a certain perishable product sold by AHOLE Inc is given by the following distribution:
Demand Probability
8 0.1
9 0.2
10 0.1
11 0.4
12 0.2
The product cost AHOLE $5 each. the product sells for $11 each. if not sold by the end of the week, the leftover units must be scrapped.
The supplier only has 10 or 11 units available for AHOLE to purchase. how many would you recomend AHOLE to purchase based on expected profit? (10 or 11)
What is the maximum expected profit?
Im stuck because if AHOLE can only purchase 10 items, does that factor the demand of 11 and 12 out of the question? if so, would this effect the probability of the other (8 9 10) demand since these would be eliminated? can anyone try and lead me into the right direction? THanks for your help
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11-04-2011, 01:27 PM
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#1994
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veteran
Join Date: Feb 2011
Posts: 2,833
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Re: The Official Math/Physics/Whatever Homework questions thread
If the demand were 11, but AHOLE only had 10 units, how many would they sell? How much profit or revenue would they get. If the demand were 12?
Now, if AHOLE had 11 units, ...
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11-04-2011, 03:14 PM
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#1995
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grinder
Join Date: Dec 2010
Location: T.Dot
Posts: 493
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Re: The Official Math/Physics/Whatever Homework questions thread
Quote:
Originally Posted by coffee_monster
If the demand were 11, but AHOLE only had 10 units, how many would they sell? How much profit or revenue would they get. If the demand were 12?
Now, if AHOLE had 11 units, ...
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im lost, sorry i dont follow?   
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