Quote:
Originally Posted by tilted
Hi, guys.
I'm having trouble with a problem and am hoping someone on here can help me out.
I need to find the derivative of the inverse function at the point a= -2 assuming x > 0
The function given is f(x)= e^3x + 2e^x - 5
I tried solving for the inverse and failed.
I also tried to solve for x when f(x) = -2 and failed.
Any help is appreciated.
thanks
i was considering such a problem when dealing with a numerics issue a while back and i found that since you essentially flip the graph over the x=y line to get the inverse function, we can think of the derivative of dy/dx as a vector [dy dx]
then do the matrix the flips over y=x and get [dx dy] then inpret that as the flipping of a fraction and getting 1/f'(x) = d/dx (f_inv(x)).
then i was thinking you could use this to model the movement of a functions root along a function f(x) + e along the x-axis by doing like the (root of f(x)) + 1/integral(root,root+e)(f'(x))dx or (root of f(x)) + integral(root,root+e)(1/f'(x)dx) or something of the like. is there anything i should look into involving this?