Math problem from: Classic Article: No Limit Hold 'em Problem - Books and Publications

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Math problem from: Classic Article: No Limit Hold 'em Problem

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02-09-2012 , 12:13 PM

cubaman

newbie

Join Date: Nov 2006 Posts: 36

here is the article:
http://www.twoplustwo.com/magazine/i...em-problem.php

$

Quote:

Let’s see how various bet sizes do. How about $1,010? That forces him to fold his straight draw, but costs you all that money when he has his hand. Your expected value is 80 percent of $1,000 minus 20 percent of 2,010. That’s $598 which is worse than if you had checked.

The way Sklansky is getting his result -> i can´t understand.

Why is he taking 20% of 2010$ and not 20% of 1010$ (the betsize / the "risk")?
By the way: when you take 20% of 2010$, which is 402$, and then substract that fom (80%*1000=)800$ you get 398$, not 598$??

I would calculate:
80% from 1000$ (Pot) = 800$
minus
20% from 1010$ (Bet) = 202$
which gives me an EV of 598$

Can someone check this and tell me what´s right? Maybe he just misstyped the number? He confused me :d

Thanks a lot

Last edited by cubaman; 02-09-2012 at 12:37 PM.

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02-10-2012 , 07:23 AM

u cnat spel

old hand

Join Date: Jul 2009 Posts: 1,964

You are correct. Dead money in the pot does not belong to us.

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02-14-2012 , 11:15 PM

au4all

veteran

Join Date: Apr 2011 Posts: 2,872

Quote:

Originally Posted by cubaman

here is the article:
http://www.twoplustwo.com/magazine/i...em-problem.php

$

The way Sklansky is getting his result -> i can´t understand.

Why is he taking 20% of 2010$ and not 20% of 1010$ (the betsize / the "risk")?
By the way: when you take 20% of 2010$, which is 402$, and then substract that fom (80%*1000=)800$ you get 398$, not 598$??

I would calculate:
80% from 1000$ (Pot) = 800$
minus
20% from 1010$ (Bet) = 202$
which gives me an EV of 598$

Can someone check this and tell me what´s right? Maybe he just misstyped the number? He confused me :d

Thanks a lot

You're both coming up with the same answer (598). I agree David's explanation is a little awkward.

Last edited by au4all; 02-14-2012 at 11:22 PM.

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02-28-2012 , 05:03 PM

Redred

banned

Join Date: Mar 2006 Posts: 62

The mistake is in the following part;

"Let’s see how various bet sizes do. How about $1,010? That forces him to fold his straight draw, but costs you all that money when he has his hand. Your expected value is 80 percent of $1,000 minus 20 percent of 2,010. That’s $598 which is worse than if you had checked."

The lost should be 20 percent of 1010, which is the correct way to calculate EV.

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03-02-2012 , 05:19 AM

R Gibert

adept

Join Date: Jan 2006 Posts: 936

Quote:

Originally Posted by cubaman

You're right. He made a mistake. I'll give 3 ways of computing the EV:

.80*1000 - .20*1010 = 598
.80*2010 - 1010 = 598
1000 - .20*2010 = 598

It appears DS got #1 mixed up with #3 with his:

.80*1000 - .20*2010 = 398

He actually wrote the right answer 598 using an incorrect method that should have yielded the incorrect 398.

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04-08-2012 , 02:52 AM

All-inMcLovin

Wholesome Mod

Join Date: Oct 2007 Posts: 49,539

Does OP win a prize now?

Nice find!

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