Odds of opponent having straight flush
02-21-2017
, 12:05 AM
02-21-2017
, 07:15 AM
02-21-2017
, 07:31 AM
Jkjk.
Since you block the 5
, this is pretty easy. It looks like you ran it twice on the river, so lets assume we're thinking about this problem on the turn.
4 cards on the board and 4 cards in your hand imply there are 52 - 8 = 44 unseen cards. Your opponent has a straight flush when he has T9 in his hand, and any two other cards. The number of these hands is:
(42 choose 2) = (42 * 41)/(2 * 1) = 861.
All the possible hands your opponent could have is:
(44 choose 4) = (44 * 43 * 42 * 41)/(4 * 3 * 2 * 1) = 135,751.
Meaning the probability your opponent has a straight flush on the turn (assuming he has 4 random cards) is:
861/135,751 = 0.6%.
The only use to this information is that you can never profitably fold.
Since you block the 5
, this is pretty easy. It looks like you ran it twice on the river, so lets assume we're thinking about this problem on the turn.4 cards on the board and 4 cards in your hand imply there are 52 - 8 = 44 unseen cards. Your opponent has a straight flush when he has T
9 in his hand, and any two other cards. The number of these hands is:(42 choose 2) = (42 * 41)/(2 * 1) = 861.
All the possible hands your opponent could have is:
(44 choose 4) = (44 * 43 * 42 * 41)/(4 * 3 * 2 * 1) = 135,751.
Meaning the probability your opponent has a straight flush on the turn (assuming he has 4 random cards) is:
861/135,751 = 0.6%.
The only use to this information is that you can never profitably fold.
Last edited by ThisKid$Tough; 02-21-2017 at 07:53 AM.
02-21-2017
, 05:12 PM
02-22-2017
, 06:18 AM
Quote:
Jkjk.
Since you block the 5, this is pretty easy. It looks like you ran it twice on the river, so lets assume we're thinking about this problem on the turn.
4 cards on the board and 4 cards in your hand imply there are 52 - 8 = 44 unseen cards. Your opponent has a straight flush when he has T9 in his hand, and any two other cards. The number of these hands is:
(42 choose 2) = (42 * 41)/(2 * 1) = 861.
All the possible hands your opponent could have is:
(44 choose 4) = (44 * 43 * 42 * 41)/(4 * 3 * 2 * 1) = 135,751.
Meaning the probability your opponent has a straight flush on the turn (assuming he has 4 random cards) is:
861/135,751 = 0.6%.
The only use to this information is that you can never profitably fold.
Since you block the 5
, this is pretty easy. It looks like you ran it twice on the river, so lets assume we're thinking about this problem on the turn.4 cards on the board and 4 cards in your hand imply there are 52 - 8 = 44 unseen cards. Your opponent has a straight flush when he has T
9 in his hand, and any two other cards. The number of these hands is:(42 choose 2) = (42 * 41)/(2 * 1) = 861.
All the possible hands your opponent could have is:
(44 choose 4) = (44 * 43 * 42 * 41)/(4 * 3 * 2 * 1) = 135,751.
Meaning the probability your opponent has a straight flush on the turn (assuming he has 4 random cards) is:
861/135,751 = 0.6%.
The only use to this information is that you can never profitably fold.
Thanks so much wow so this dude ripped me off for a 1 in a 135,751 lotto.
02-23-2017
, 04:04 AM