Hi, I was hoping you guys could help me out with three situations and how they are handled for calculating what a pot sized bet is.

All situations are for 2-2 PLO.

First situation: New player at the table posts $2. First player's turn to act and he pots it. Is his bet $8? or $10?

Second situation: Small blind gets up from the table resulting in a dead small blind. First player to act pots it. Is the bet $6? or $8?

Third situation: Someone misses their blinds and come back to the table. They post $2 and surrender $2. First player to act pots it. Is the bet $8? $10? or $12?

Thanks in advance guys.

The largest amount suggested in each case

Pot size raise = $ in the pot + your call

I know how to calculate it. Was just wondering if posts, surrenders, and dead blinds changed anything. So the only thing that changes is a dead small blind? You count it as being there for the raise size?

Pot size raise=3 times the last raise(or a limp, whatever) + what is in the pot.. Your own blind, raise, limp or posting doesn't count.

First: Depends of rules. In some live games the posted blind doesn't count when calculating pot, so 8/10. In online games it always counts, so 10.

Second: Bb is the last "raise" and there is no money on the pot, so 3x2=6.

Third: Same thing as in first situation.

I could never play any live PL game, it'd took me 10 seconds every single time to figure out how much is a pot size bet. And that wouldn't even include the time I'd waste trying to count the chips.

Thanks god for online poker.

I really don't know, but isn't $10 the correct answer in last one?

SlimyF's way is another way of counting it.

Online it's 12, if "surrender" means the dead blind which goes in the middle. At live games it depends.