index of all the parts of this series
tl; dr
A 5000th post is traditionally used to pass on some stunning strategic insight, helping the rest of you to crush even more than you already do. And if I knew more about the game, that’s what I’d attempt, but I don’t, so this will have to do.
There's a regular - one might almost say unending - stream of questions in Beginners about the basic mathematics of poker. Guys who are struggling with pot odds, implied odds, pot equity, fold equity, how often someone needs to fold for a bluff to be profitable, do I need to multiply by 2 or 4? etc etc. All good stuff, and there are plenty of books and articles out there that will answer all these kind of questions, but for my 5000th post, I thought it might be fun to start a thread here in Beginners which outlines, in a systematic way, some of these key concepts.
This is for Beginners. It's going to be basic. We're not going to get into Game Theory, Nash Equilibria, or reverse implied fold equity (whatever that is). If you're happy working out the Expected Value of a turn semibluff shove, this isn't for you, except that some of you guys will know more about this stuff than I do, so please chip in and add your own insights and do a better job of explaining some of this stuff than I will. And if you have questions, or something isn't making sense (entirely possible when it's me doing the explaining
) then remember the First Rule of Beginners: nobody's allowed to feel awkward about not understanding something. Fire away. No such thing as a stupid question.
Right off the top of my head I'm thinking we should talk about stuff like:
- probability
- combinatorics
- expected value
- equity
- counting outs
- pot odds and implied odds
- bluffing (and semibluffing)
I’m assuming you’re comfortable with basic arithmetic, simplifying fractions, switching quickly between decimals, percentages, and fractions etc. If you’re not, just say so, and someone in this thread will help you get sorted.
We're going to need more than one post for this. Not sure how many. Let's make a start and see what happens.
PROBABILITY
We live in an uncertain world. We play a game that is centred around uncertain outcomes. In everyday language we use words like 'unlikely', 'possible', 'certain', 'favourite', 'underdog' etc to describe these events.
Probability is the mathematician's way of quantifying the likelihood of something happening. It's a tool which poker players can use to make better decisions.
Probabilities are measured on a scale which runs from 0 to 1.
An event that is impossible is assigned a probability of 0.
At the other extreme, something that is certain to happen is given a probability of 1.
Everything else is somewhere in between.
A lot of the probabilities we'll want to talk about can be determined accurately.
If I pick a card at random from a full deck, there are 52 cards, and 26 of them are red.
So the probability of picking a red card = 26/52 = 0.5 = 50%
(Note then, that a probability can be expressed as a fraction, a decimal, or as a percentage. Use whichever you prefer.)
This is sometimes written as p(red card) = 0.5
There are 13 hearts, and 39 non-hearts. in a full deck.
So p(heart) = 13/52
and p(non heart) = 39/52
Note that p(heart) + p(non-heart) = 13/52 + 39/52 = 52/52 = 1
(Hopefully, this makes sense since we must get either a heart or a non-heart. There are no other possibilities. We're therefore certain to get one or the other.)
If A is some event which may or may not happen, then
p(A) + p(not A) = 1
So p(A) = 1 - p(not A)
It's quite common, when trying to work out the probability of something happening, that's it actually easier to work out the probability of it NOT happening. We can then subtract that probability from 1, to find the probability we're actually interested in.
Note that when we said
p(heart) + p(non-heart) = 1
we were dealing with two
mutually exclusive events. That is, it's not possible to select a card which is both a heart AND a non-heart.
But it's possible to have a situation where the two events we're interested in are not mutually exclusive.
For example, if we pick a card at random, what is p(Heart OR Ace)?
We could start by simply counting the number of qualifying cards.
There are 13 Hearts, and 4 Aces, but one of those Aces is already counted in the 13 Hearts.
So 13 Hearts, and 3 non-Heart Aces, makes 16 cards all together.
So p(Heart OR Ace) = 16/52 = 4/13
Our general rule for working out p(A OR B) where A,B are two events is as follows:
p(A OR B) = p(A) + p(B) - p(A AND B)
where p(A AND B) is the probability of both events happening at the same time (which will equal zero if the two events are mutually exclusive, because that's what mutually exclusive means).
Let's use this rule to check our calculation of p(Heart OR Ace)
We know p(Heart) = 13/52 = 1/4
and p(Ace) = 4/52 = 1/13
What is p(Heart AND Ace)?
There's only one card that is both a Heart AND an Ace - the Ace of Hearts.
So p(Heart AND Ace) = 1/52
So our rule gives us:
p(Heart OR Ace) = p(Heart) + p(Ace) - p(Heart AND Ace)
= 1/4 + 1/13 - 1/52
= 13/52 + 4/52 - 1/52
= 16/52
= 4/13
which is the same result we got by counting the qualifying cards.
If you want to play along, try these:
If we pick a single card at random from a full deck, what is
(a) p(a Broadway card)
(b) p(a Broadway card OR Club)
(c) p(a black wheel card)
(d) p(a wheel card which is not a 3 or a Diamond)
Sometimes we’ll be interested in two
independent events. Events are said to be independent if the occurrence (or non occurrence) of one of them has no impact at all on the likelihood of the other occurring. For example if I spin a coin and roll a die, the result of the coin (Heads or Tails) is totally independent of the result of the die (1,2,3,4,5, or 6).
In sports (here in the UK) Wolves winning the Premier League and Exeter winning League One are clearly independent events (they also happen to have vanishingly low probability but that’s another matter). However betting events like ‘
Manchester United will beat Liverpool this Saturday’ and ‘
United’s Wayne Rooney will score three goals’ are most certainly
not independent. (If all you learned about the game afterwards was that Rooney had scored three goals, that would absolutely change your view about how likely it was that Manchester United won the match.)
We have a simple rule for dealing with the probability of two independent events both happening:
p(A AND B) = p(A) x p(B)
So if I spin the coin and roll the die,
p(Heads AND 4)
= p(Heads) x p(4)
= 1/2 x 1/6
= 1/12
(exactly the result you’d get if you were to list all possible outcomes:
(H,1),(H,2) …. (T,5),(T,6)
a list of 12 outcomes, of which (H,4) is just one.)
An obvious application of probability in poker is to calculate the likelihood of being dealt different kinds of hands preflop. But before we do that, it would be useful to know a little about
combinatorics. We’ll talk about that in the next part.
Last edited by AlienSpaceBat; 03-03-2012 at 07:46 AM.
Reason: added index link