Quote:
Originally Posted by NaZz68
I can't seem to figure out how to calculate this. (formula)
K on the board, so 3 kings unaccounted for. 4 aces are unaccounted for.
Multiply kings by aces to get the total number of AKo/AKs combos.
3x4 = 12
3 of those must be suited, because the K on the flop removes one of the 4 AKs that are possible pre. So if there's 12 of AKo/AKs, including 3 of AKs, there must be 12-3 = 9 of AKo
If you think that's tricky, wait till you try counting two pair combos if villain only plays suited varieties of some hands.
e.g. Tc 9c 5s allows 3 combos of T9s (spades, diamonds, hearts), but Tc 9s 5c only allows 2 combos of T9s (diamonds and hearts).