Originally Posted by Adz
Bet 5 on black, if lose bet 10, if lose bet 20, if lose bet 40, when win go back to origional 5 bet and repeat.... in theory for 30 spins an hour you should win 50% of time,
so 15 x $5 is $75 hourly rate.... as long as your rolled to cove a big loss streak you will always make $5 on a win and break even on a loss because you make second bet bigger!!!.
Yes, I see a flaw in your example.
your 4 step Marty risking $75 to double up is not a 50/50 prop.
18/37 = 33.92% chance of success to double your $75 stake.
You would have to win 15 times in a row
with a win probability of 93.05% [1-(1-18/37)^4]
avg number of spins = 29
18/38 = 30.19% to double the $75 stake.
avg number of spins = 30
You got the number of trials right.
Of course you can have some winnings IF and when the 4 losses in row happen.
A much larger bankroll will increase your winning probability of doubling a stake, but you can do the math on that.
At times a Martingale can give the highest probability of hitting a win goal. This is the concept, a real good math exercise also, known as Bold Play.
Maybe BruceZ has done the math for the Red and Black game in another thread.