Originally Posted by willyc
No. The house edge does not equal the probability of losing a hand.
On average you lose about 48% of hands. Losing 10 in a row is therefore approximately .00065 = .065%
Just a question, if playing BlackJack, you only lose 48% of the hands you play and sometimes they pay you 3 to 2 on your wins, but your losses are flat, how is there a house edge? Am I missing something here? Seems like losing 51 or 52% of your hands played would make more sense.....someone please splain to me.