Quote:
Originally Posted by Aces123123
If you play two 1 in 4 shot, you don't win anything 9 out of 16 times. If you play one 1 in 2 shot you don't win anything one out of 2 times, or 8 out of 16 times. So slightly higher chance to win. So based on this I think you are slightly more likely to miss playing 10 times for 7 coins compared to playing once for 70 coins. I wish someone would share the math
In your example, there's a 6.25% chance you win twice with the 1 in 4 shots, which equalizes the EVs presuming the jackpot stays the same.
In the deal, because we are dealing with such low probability events, the EV of winning more than once is basically 0, making the difference between betting 7 coins and 70 coins basically 0 in terms of probability of hitting the jackpot at least once (the EV wrt to the jackpot portion only is identical.)
By my calculations, if you spent 7000 coins each on either buyin amount, you will win the jackpot at least once:
0.1537894580% using 7 coin spins
0.1537905223% using 70 coin spins
*Note when I say hit the jackpot, I mean advance to the jackpot round.