Yes. Having a prior distribution of the populations win-rates (i.e. the average win-rate and the standard deviation) would make it possible. Let's say that the true population win-rate is -1.5BBs / 100 and the standard deviation is 40BB / 100. Let us further assume that win-rates are normally distributed.
Est. True Win-rate =
-1.5 / 40
2 + 13.42 / 57.79
2 Divided by
1/40
2 + 1/57.79
2
The standard deviation around this estimate would be:
sqrt[ 1 / (1/40
2 + 1/57.79
2) ]
So for your numbers we would get an estimated true win-rate of 3.33 with a standard deviation of 32.89. Of course, if you have a different population distribution or if certain assumptions cannot be met, these results won't be accurate.
At least this is the sort of calculation I argue for in another thread that no one seems to have destroyed yet:
http://forumserver.twoplustwo.com/25...cture-1161363/