Banzai is correct, I made a rookie mistake. I computed A's best value of a, but didn't check to see if it gave a positive net expectation. It didn't.
Assuming my original solution had been correct, A always loses if called if he bets with numbers between 20 and 40. So he might as well use 0 to 20 instead, that is bet with 0 to 20 or 40 to 100. That costs him nothing when he bets, and it doesn't change B's optimal strategy. But if when A checks, he now wins 30% of the time instead of 10%. This is enough to make it a winning strategy.
Quote:
Originally Posted by bigpooch
You worked out the problem for potsize P = 2 bets; work it out again for P = 1 !
It says "potsize" bet after A and B ante (I set the ante at 1).
Last edited by AaronBrown; 08-05-2010 at 10:31 PM.