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 Probability Discussions of probability theory

 06-04-2012, 04:17 PM #1 newbie   Join Date: May 2012 Posts: 41 simple (not so much for me) math question say the pot OTT is 37.5 bb's after my opp. called. I am out of position and want to lay my opp. 1.85:1 by betting out. So: x+37.5/x = 1.85 How do i find x in a simple way? Ty!!
 06-04-2012, 04:45 PM #2 Carpal \'Tunnel     Join Date: Feb 2006 Location: Austin, TX Posts: 15,098 Re: simple (not so much for me) math question I assume you meant to have parens there like (x+37.5)/x = 1.85 So then 1.85x = x + 37.5 1.85x - x = 37.5 .85x = 37.5 x = 37/.85 Put another way, if you want to give them 1.X : 1 odds, then bet P/X. The result is, the pot odds will be (P + P/X) : P/X multiply both sides by X/P X/P*(P + P/X) : 1 X*P/P + X*P/P*X : 1 X + 1 : 1
06-04-2012, 05:19 PM   #3
newbie

Join Date: May 2012
Posts: 41
Re: simple (not so much for me) math question

Quote:
 Originally Posted by RustyBrooks I assume you meant to have parens there like (x+37.5)/x = 1.85 So then 1.85x = x + 37.5 1.85x - x = 37.5 .85x = 37.5 x = 37/.85 Put another way, if you want to give them 1.X : 1 odds, then bet P/X. The result is, the pot odds will be (P + P/X) : P/X multiply both sides by X/P X/P*(P + P/X) : 1 X*P/P + X*P/P*X : 1 X + 1 : 1
I see Ty sir!

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