Off-topic but might be fun!
I was playing Scrabble with my Dad earlier today. To decide who would play first we each drew a tile - the person with the tile closest to A would start the game.
I drew an R, then Dad did the same. We put both tiles back then I drew an O, then Dad did the same. We again put the tiles back. I then drew an M, and Dad did the same!
There were 98 letters in the bag. There were 6 letter R's, 8 O's and 2 M's when we started. I've calculated the probability of each of us drawing those letters as follows, taking into account the fact that there were only 97 tiles each time Dad drew, and of course one fewer of that particular letter each time (i.e. 6 in 98 chance of me drawing an R, 5 in 97 for Dad).
R - 6.1%
O - 8.2%
O - 7.2%
M - 1%
We're wondering what the probability was of us drawing the same letter as each other on three consecutive occasions. Can anyone help? Thanks in advance! email@example.com