Originally Posted by jay_shark
At an n-handed table, the exact probability that two players get dealt pocket aces is,
where C(n,2) is the number of ways that you can select 2 objects from n total objects.
At a 10-handed table table, this is ~ 0.0166 %
I realized that I calculated the probability that someone at the table is dealt pocket aces. The second term in my op, which is
C(n,2)*6/C(52,2)*1/C(50,2), is the probability that two players at an n-handed table are dealt pocket aces.