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AA v AA

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01-11-2010 , 08:38 AM

PokerRon247

Carpal \'Tunnel

Join Date: Jul 2008 Posts: 11,192

How do you work out the probability of AA v AA on a 9 handed NLHE table?

Just asking because although I've seen it plenty of times, I've just seen it back-to-back on the same table, with one player involved in both hands.

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01-11-2010 , 11:18 AM

jay_shark

Pooh-Bah

Join Date: Sep 2006 Posts: 3,655

As it was done in a recent post, the probability is

C(9,2)*6/C(52,2)*1/C(50,2) which can be simplified to

C(9,2)*1/C(52,4) ~ 0.0133 %

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