Originally Posted by Jerrod Ankenman
Yeah, I see why this is confusing.
p(call) here is the probability that this matchup occurs given that you hold AKs. So if you have AKs, there are 3 ways to make AA, 3 ways to make ATs, and 3 ways to make A5s. But there would be 6 ways to make QQ, for example. So what's in the table is right.
Oh wow, i'm stupid. I looked at it the wrong way. thank you very much.
My mind, btw, is fully blown by the fact that you were the one who answered. So awesome!
PS: Free dinner on me (at a nice place) if you're ever around Wilton, CT