Was working out the Jam/Fold strategy but got stuck on this page. They have a table calculating expected value of the caller when the caller will call with AKs vs AA, later AT and then A5s.

The first matchup (AA vs defender's AKs) I don't understand. The equity is correct and all but the Probability of calling is shown to be 3/1225. I don't understand this. If 2 As are out there should only be 2/1225 probability of calling. The 3/1225 makes sense for the other 2.

I must be missing something. I found an Errata for this exact page but it seemed to correct it to what i'm seeing here so i'm probably wrong somehow.

thanks

Yeah, I see why this is confusing.
p(call) here is the probability that this matchup occurs given that you hold AKs. So if you have AKs, there are 3 ways to make AA, 3 ways to make ATs, and 3 ways to make A5s. But there would be 6 ways to make QQ, for example. So what's in the table is right.

Oh wow, i'm stupid. I looked at it the wrong way. thank you very much.

My mind, btw, is fully blown by the fact that you were the one who answered. So awesome!

thanks again.

PS: Free dinner on me (at a nice place) if you're ever around Wilton, CT