Quote:
Originally Posted by Mr.Jones
1/3^7
is it .0457% of the time you lose all 7 in a row?
My orginal example had nothing to do with roulette, I don't play in the pits, but that leads me to this question now.
So would the odds of losing 3, 1-12 spins, in a row be 12/38^3 or you will lose all 3 3.1% of the time?
3.1% is the chance for WINNING 3 in a row.
(26/38)^3 is the prob. of losing 3 in a row
The probability of winning w and losing n-w in n independent trials is
C(n,w)*(p^w)*q^(n-w)
where p is the winning chance on 1 independent trial.
This is called the binomial distribution. Look on any stat site.
