I was thinking... According to the Monty Hall problem, knowing that the sheep wasn't behind a certain door did not mean a change of the initial probability.
Wouldn't it be applicable in poker when everybody folds to the button? IE in a full ring game, if there was an X% chance that at least one opponent would have a Sklansky group 1 hand, and everybody folded to the hero on the button, doesn't it mean that the SB and BB now have the probability of the entire table to have the said hand?
Your thoughts on this would be highly appreciated.