Hey everyone,

Was wondering what the probability of having a pair in your hand in PLO was. I know in Hold'em its 6% but I don't think I can just double that.

If you could let me know and what the formula used to get it was that would be great.

Thanks!

Also would like to know the probability of pairing; pretty sure its around 65/66% because you have twice the amount of cards as in Hold'em.

Chance to be dealt at least one pair with 4 cards:

1 - (48/51 * 44/50 * 40/49) = 32.4%


And if we exclude trips (0.92%), 2 pairs (1.04%), and quads (13/270725), the chance for exactly one pair is 30.4%.

That's great thanks!

Any idea if I am correct about pairing?

Anyone know what the odds of two pairing in PLO would be?

Thanks

Is your question, what is the chance to be dealt 2 pairs? That would be about 1%.

No sorry, I mean two pairing on the flop- assuming 4 different cards in hand

Starting with 4 different cards, there are 12 cards that can hit us on the flop, and you want to see 2 of those of different ranks. I think the solution is:

12/48 * 9/47 * C(3,2) = 14.4%

Didn't you leave out the third card not matching the hand or other flop cards? If you include it, with prob= 36/46, you get 11.24%.

Using combinations

Prob(exactly 2 pair on flop in PLO given 4 non-matching hole cards) =

C(4,2)*C(3,1)*C(3,1)*C(36,1)/C(48,3) = 11.24%

Yes, I included full houses and also included the possibility of being counterfeited by a board pair.

That's awesome, very helpful!

Thanks you!

Addendum:
The flop can pair 3 of the 4 cards in your hand, which will still be a 2 pair hand in Omaha. So, if OP wants to include this possibility, the added probability is

C(4,3)*(3^3) / C(48,3) = 0.6%.