Quote:
Originally Posted by walkby
I think there's a 28.6% chance to flop a pair,
It's not perfectly clear to me what you want.
If you're talking about Texas hold 'em and you hold, for example, AK, there are 3 missing aces, 3 missing kings, and 44 missing cards which are neither aces nor kings.
In a three card flop where we are not interested in suits, and not interested in permutations, here are all the possible combinations:
AAA,
AAK,
AKK,
KKK,
AAN,
AKN,
KKN,
ANN,
KNN, and
NNN.
And here are the possible ways to make each of the above combinations:
1---AAA,
9---AAK,
9---AKK,
1---KKK
132---AAN,
396---AKN,
132---KKN,
2838---ANN,
2838---KNN, and
13244---NNN.
That should all add up to C(50,3)= 19600. Does it?
1+9+9+1+132+396+132+2838+2838+13244=19600.
(That was our check).
Since you hold AK, if you want just flops that have an ace or king, in order for you to flop a pair of aces or a pair of kings, there are 5676 of those flops.
Finally 5676/19600= about 29%.
(Or if you count flops that have exactly a pair of something other than ace or king and no aces or kings as flopping a pair, we'd get a different number).
Quote:
I estimate for the past 50,000 hands or so I'm flopping a pair at about a rate of 1 for every 10 flops, maybe lower. I haven't been tracking this so I could be unintentionally exaggerating my bad luck but I feel this is close to correct. What are the odds of this happening over a 50,000 hand sample (using the rate of 1 in 10)?
At the rate of 1 in 10, the odds of not flopping a pair would be 9 to 1.
But as you see from above, when you hold AK, the odds of not flopping 1 ace or 1 king are 13924 to 5676 or about 2.453 to 1.
Buzz