Quote:
Originally Posted by whosnext
To anticipate one of the standard responses, are you asking what are the odds that two opponents on a 7-handed table have AKs and AA when you have AKs or are you asking what are the odds that AKs, AKs, and AA all are dealt on a 7-handed table?
Indeed that would have been my response
I'll just answer both.
#1: C(6,2) * 3 / C(50,4) / 3!! = 1 in 15353.333...
#2: C(7,3) * C(4,4) * C(4,2) / C(52,6) / 5!! = 1 in 1,454,180 exact
There's only one valid way to group the cards since the AK hands have to be suited.