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 06-15-2012, 12:49 PM #1 newbie   Join Date: May 2012 Posts: 38 4bet jamming on 2 or more players...the math!? Ok, 6 max trny. hero: bb, 35 bb's utg+2 : 100 bb's btn: 100 bb's (eff. stacks 35, w/e) utg+2 opens with minraise, btn 3 bets to 5 bb's, so about 10 bb's in pot. I have Ac2c. OR opens 30%, btn 3bets 5%. I want to jam but like to do the math first (hypothetically) How do we quantify the times both players fold or call to get our fold equity? I know how to do this heads up but get a lil' lost when it's multiway. for short, I'd like to get the average FE amount when taken every outcome in consideration. dunno, makes sense? TY!
06-16-2012, 11:58 AM   #3
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Join Date: May 2012
Posts: 38
Re: 4bet jamming on 2 or more players...the math!?

Quote:
Ty sherman, it was this part I was a little unsure about, although it's logical enough. Yes there were antes, so bout 10 bb's. also, cutoff, yes of course.
ty sir. Guess that makes this a pretty easy shove then

Isn't there a math rule that you can quantify any probability as long as they are not independant? What is a simple way to determine if something is independant or not? #mathnoob.

 06-16-2012, 01:16 PM #4 Carpal \'Tunnel     Join Date: Jun 2005 Location: Psychology Department Posts: 7,423 Re: 4bet jamming on 2 or more players...the math!? They are independent if the outcome of one event does not depend on the outcome of another event. For example, the second hand you are dealt in a hold'em game does not depend in any way on the first hand you were dealt. The hands are independent. In your situation, you can assume independence even though there is not. The Button's decision will depend on the CO's decision at least some of the time. So their decisions (whatever they may be) are not independent. However, to make the math easier it is often useful to assume they are independent...particularly when the dependencies are small (as in this case). Here is an example of how they are not independent though. Some players like to "keep players honest" so if the CO folds, the Button might decide to widen his calling range. For what it is worth, I am pretty sure the play is going to be -EV without doing the math. If the button is only 3 betting 5% of all hands he is dealt, he already has a very narrow range. Therefore, you will not get them both to fold very often. In addition, his narrow range probably crushes your A2s hand. So you will have little equity when called. Little equity from folds and little equity when called = probably a -EV play.

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