Well this is my first attempt at this, but here's what I got.
I believe the overall odds are 1 in 978.8 Million. That is assuming it happens the way it did in the WSOP (pocket aces and pocket royal flush cards), the quads having only 1 ace, OR the RF having only one hole card to it.
To answer your post more specifically...
Quote:
Originally Posted by frankie2
Quad Aces (two aces in hole) lost to a Royal Flush. I'm sure the odds are exceptionally high but 2.7 billion to 1 sounds pretty crazy. Anyone good at figuring the precise odds here.
Assuming quad aces with two in the hole, BUT the RF had either 1 OR 2 in the hole, the odds would be 1 in 1.646 Billion.
And finally, the odds of both players having both cards to their hand in the pocket, 1 in 4.39 Billion.
OK - someone please tell me why I'm wrong
. I'm not sure if the number of opponents matters, it would definately have to icrease the odds of 2 players starting with the 2 hole cards to make this happen though. My numbers assume heads up (if it makes a difference).
I also am not sure if it matters if player 1 has quads and player 2 has a RF OR if player 1 has a RF and player 2 has quads...but I don't think it does.