Originally Posted by tringlomane
Now we need to have A234 to be a rainbow, and the 5 can be of any suit.
There are 24 ways to arrange A234 into four suits: 4*3*2*1 = 24, and 4 ways to choose the suit for the 5. Giving a total of 96 combinations that give (A234r)5.
The total ways to choose 5 cards from 52 is 52*51*50*49*48/(5*4*3*2*1) = 2,598,960
So the probability is 96/2,598,960 = 1 in 27072.5
And I thought me getting a dealt badugi on Stars (~1 in 11,280) and getting chopped on the river was bad!
Especially bad since we play mid stakes NL...the dealt badugi was milking the table for 50 pre/1/2 draw...then over 1000 goes in on river!
We also play a three card variant, where A23 is the nuts, and you need a three card badugi to chop...this was created since we have 7-8 players usually, and everyone loves these games.
What are the odds of being dealt a three card A23, and then a A23 badugi?