Learning c++ on my own - why would printing *yPtr output 0?

1 #include <iostream >
2 const int ARRAY_LEN = 10;
3
4 int main() {
5 int arr[ARRAY_LEN] = {10}; // Note implicit initialization of
6 // other elements
7 int *xPtr = arr, *yPtr = arr + ARRAY_LEN -1;
8 std::cout << *xPtr << ’ ’ << *yPtr; // Should output 10 0
9 return 0;
10 }

from my understanding, line 5 initiates an array of 10 elements, all of which are equal to 10.

Then line 7, *yPtr is a pointer that points to the first element of "arr", plus 10 - 1 ie 9 elements past the first element of "arr", ie the 10th element of the array which is equal to 10. Yet cout << *yPtr outputs 0, not 10. What it do?

Thanks in advance.

nvrmind just realized line 5 initializes all elements 1-9 as 0

Yes, if you don't specify enough elements in the initialization, the unspecified elements get set to zero.

Good job using const int instad of #define tho.