Search function with lists [ipython] - Computer Technical Help

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Search function with lists [ipython]

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10-30-2015 , 10:56 AM

AsUs91

newbie

Join Date: Jun 2012 Posts: 48

Hey, maybe here is some1 who can help me.
Is their any function in ipython that compares 3char of my input with any object in my list and print me all objects with the same 3chars.
for example my list

A=['ZZo(0.25)','YQa(0.75)','ABz(R 0.75)',['ABz(L 0.25)']]
now when i press ABz i want that the searchfunction prints me
ABz(R 0.75) ABz(L 0.25)

maybe it will look like this(pseudocode)
if input == position(0,1,2)of any object in List A then print the objects

Hope some1 can help me

regards

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10-30-2015 , 11:30 AM

econophile

Carpal \'Tunnel

Join Date: Jul 2005 Posts: 11,319

one way to do it

Code:

for item in A:
    if item[0:3]==input:
        print(item)

Quote

10-30-2015 , 12:10 PM

AsUs91

newbie

Join Date: Jun 2012 Posts: 48

Quote:

Originally Posted by econophile

one way to do it

Code:

for item in A:
    if item[0:3]==input:
        print(item)

Hey, thanks for your help

I tried to build the function but when i use it ,it prints only one object.
Where is my mistake?
regards

[PHP]def searchinlist(input):
for item in A:
if item[0:3]==input:
print(item)
[/PHP]

[PHP]searchinlist(ABz)

['ABz(L 0.25)']
[/PHP]

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10-30-2015 , 12:13 PM

econophile

Carpal \'Tunnel

Join Date: Jul 2005 Posts: 11,319

The last element of your list above is a list rather than a string.

If you change A=['ZZo(0.25)','YQa(0.75)','ABz(R 0.75)',['ABz(L 0.25)']]

to A=['ZZo(0.25)','YQa(0.75)','ABz(R 0.75)','ABz(L 0.25)']

then it should work. Unless there is some reason that some of the elements in your list should be lists.

Quote

10-30-2015 , 12:54 PM

AsUs91

newbie

Join Date: Jun 2012 Posts: 48

Quote:

Originally Posted by econophile

I actually thought if i have a mainlist for xxx(R x.xx)elements then in this list another list for xxx(L x.xx) elements makes it a little bit clear for me.
Im not so familiar with python so i thought i can make a lists with alot of lists inside just with adding [x,y,[z,a],[ab]] so now ive got 3lists.
But it isnt necessary. So im very happy with this function it works fine for my purposes. Thank you alot

Is it possible to give this function and the input a very short inputlook?
I tried this
[PHP]b = searchinlist[/PHP]
[PHP]b('ABz')[/PHP]
this works well.Is it possible to reduce this even more.
For example just press b space bar and then ABz without ''
So something like bABz or b ABz
regards

Quote

10-30-2015 , 01:18 PM

econophile

Carpal \'Tunnel

Join Date: Jul 2005 Posts: 11,319

This may be closer to what you are looking for:

Code:

def searchinlist():
    input = raw_input('Enter search string: ')
    for item in A:
        if item[0:len(input)]==input:
            print(item)

Code:

>>> searchinlist()
Enter search string: ABz
ABz(R 0.75)
ABz(L 0.25)

Quote

10-30-2015 , 01:49 PM

AsUs91

newbie

Join Date: Jun 2012 Posts: 48

Quote:

Originally Posted by econophile

This may be closer to what you are looking for:

Code:

def searchinlist():
    input = raw_input('Enter search string: ')
    for item in A:
        if item[0:len(input)]==input:
            print(item)

Code:

>>> searchinlist()
Enter search string: ABz
ABz(R 0.75)
ABz(L 0.25)

That will help me. Thanks

Is it also possible to include a randomnize function to the searchfunction that will give me a random ouput .
So ABz(R 0.75) means 75% and ABz(L 0.25) means 25%.
I can also change the name of the objects when it makes it easier to implement. Maybe the form ABz(R 75.0) or anyother form is better for this task.

So when i search my list and typ ABz it will give me ABz(R0.75) with a 75% chance and ABz(L 0.25) with a 25% chance.
Maybe something with

[PHP]import random[/PHP]
[PHP]print(random.randint(1,100))[/PHP]

and then compare the 5&6char of ABz(R75.0) which is 75 with the random number. if random number is between 1 and 75 print ABz(R75.0)
if random number is between 76 and 100 print ABz(L 0.25)
their is a maximum of 3 objects that the searchfunktion give out
some examples
so maybe ABz(R50.0) ABz(L25.0) ABz(S25.0)
or ABz(R1.0)
but another question is how to separe stuff like 50,25,25
so that the computer now 50 is 1-50 25 is 51-75 and the other 25 is 76-100

maybe this randominclude is way to difficult i dont know. but perhaps someone has a idea.

regards

Last edited by AsUs91; 10-30-2015 at 02:14 PM.

Quote

10-31-2015 , 01:09 AM

iosys

old hand

Join Date: Sep 2011 Posts: 1,753

I'm not a python guy, why did they add parenthesis to print in python3.
Seems better to not have them like in python2 and also why the need of : at the end of each statement. I mean, it doesn't seem like it would be impossible to get rid of the : by checking the beginning of the line and checking eof but there is probably something basic that i'm not getting.

Like the language seems good for kids to learn and move into a more structured programming language, after they've learned the basic fundamentals but there are these inconsistencies that annoy me, when looking at the language.

This post is ugly, I'm really tired and not really caring to write it out clean.

Quote

10-31-2015 , 06:49 AM

Pahvak

centurion

Join Date: Dec 2008 Posts: 149

Works only with flattened lists.

Code:

import re
from numpy.random import choice


def find_probability(element):
    return float(re.findall(r'[+-]?\d+(?:\.\d+)?', element)[0])


def random_choice(term, input_list):
    filtered = [el for el in input_list if term in el]
    weights = [find_probability(el) for el in filtered]
    print(choice(filtered, p=weights))


if __name__ == '__main__':
    a = ['ZZo(0.25)', 'YQa(0.75)', 'ABz(R 0.75)', 'ABz(L 0.25)']
    random_choice('ABz', a)

Quote

10-31-2015 , 02:50 PM

#10

SmileyEH

Carpal \'Tunnel

Join Date: Jun 2004 Posts: 8,049

Quote:

Originally Posted by iosys

I'm not a python guy, why did they add parenthesis to print in python3.

print is now a function as opposed to a statement.

Some of the rationale is outlined in the original PEP but I understand it basically to be much improved flexibility. https://www.python.org/dev/peps/pep-3105/

Quote

11-01-2015 , 01:20 AM

#11

iosys

old hand

Join Date: Sep 2011 Posts: 1,753

Smiley what about the required colon, it seems like there could be workarounds to get rid of it and or do you know the reason for it.

I'm just thinking that the goal of the language was typically to make the simplest to write language; when I look at python, I get that vibe but maybe i'm wrong on what python is trying to be.

Anyway thanks for the reply, will take a look at the link and get some grip on the rational behind the flexibility.

Quote

11-01-2015 , 08:09 AM

#12

AsUs91

newbie

Join Date: Jun 2012 Posts: 48

Quote:

Originally Posted by Pahvak

Works only with flattened lists.

Code:

import re
from numpy.random import choice


def find_probability(element):
    return float(re.findall(r'[+-]?\d+(?:\.\d+)?', element)[0])


def random_choice(term, input_list):
    filtered = [el for el in input_list if term in el]
    weights = [find_probability(el) for el in filtered]
    print(choice(filtered, p=weights))


if __name__ == '__main__':
    a = ['ZZo(0.25)', 'YQa(0.75)', 'ABz(R 0.75)', 'ABz(L 0.25)']
    random_choice('ABz', a)

This looks very good. Works only with flattened lists means only one big list,and no lists in lists?
Is their also a option to shortcut the random_choice('ABz', a)
like only typ in ABz a or a ABz something like this
regards

Quote

11-01-2015 , 11:03 AM

#13

just_grindin

Pooh-Bah

Join Date: Dec 2007 Posts: 5,263

Quote:

Originally Posted by iosys

My understanding of the ethos of the python community is the same. Simplicity in the syntax with maximum effect.

Quote

11-02-2015 , 08:36 AM

#14

Pahvak

centurion

Join Date: Dec 2008 Posts: 149

Quote:

Originally Posted by AsUs91

Works only with flattened lists means only one big list,and no lists in lists?

Exactly.

Quote:

Originally Posted by AsUs91

Is their also a option to shortcut the random_choice('ABz', a)
like only typ in ABz a or a ABz something like this
regards

Well you can always write a new function, which uses the previous ones. Not sure if you want to be able to choose from multiple lists. For example currently there are two lists - a & b to choose from. New code:

Code:

import re
from numpy.random import choice

a = ['ZZo(0.25)', 'YQa(0.75)', 'ABz(R 0.75)', 'ABz(L 0.25)']
b = ['CCo(0.25)', 'DFa(0.75)', 'HNz(R 0.75)', 'HNz(L 0.25)']


def find_probability(element):
    return float(re.findall(r'[+-]?\d+(?:\.\d+)?', element)[0])


def random_choice(term, input_list):
    filtered = [el for el in input_list if term in el]
    weights = [find_probability(el) for el in filtered]
    print(choice(filtered, p=weights))


def random_choice_from_string(string):
    """ :param string: for example 'ABz a' """
    term, input_list_name = [s.strip() for s in string.split(" ") if s.strip()]
    input_list = globals()[input_list_name]
    random_choice(term, input_list)


if __name__ == '__main__':
    while True:
        ip = input("Insert (for example: 'ABz a' or 'HNz b'): ")
        random_choice_from_string(ip)

NB! If you use python2.7, then use raw_input() instead of input().

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11-02-2015 , 05:26 PM

#15

AsUs91

newbie

Join Date: Jun 2012 Posts: 48

Works well. Thank u alot
regards

Quote

11-03-2015 , 02:11 PM

#16

AsUs91

newbie

Join Date: Jun 2012 Posts: 48

Oh i tried to use some stuff like B8z or 88z and get the error message probabilities do not sum to 1. I think this is because we use numbers. But i thought numbers are valid in strings, so why is this not working? Is it possible and how to make the function working with numbers too? So 88z, B9z, 87z like this.
regards

Quote

11-04-2015 , 04:29 AM

#17

Pahvak

centurion

Join Date: Dec 2008 Posts: 149

Well I had no idea what your other inputs look like. Are they poker hands? Anyway the code breaks because the first occurence of a number is treated as a probability. If the input string is '88z(L 0.25)', then it uses 88, which obviously is not a probability. Just change this function to

Code:

def find_probability(element):
    return float(re.findall(r'[+-]?\d+(?:\.\d+)?', element)[-1])

Now the last number in a string is used as a probability.

Quote

11-08-2015 , 12:57 PM

#18

AsUs91

newbie

Join Date: Jun 2012 Posts: 48

Thanks now it works rlly well. Is their a easy function in python
for this programm that if the user make a wrong input for example k8sa
then ask for new input? now if i make a wrong input i get a error message.
like a do while loop in c++.
regards

Quote

11-09-2015 , 07:14 AM

#19

Pahvak

centurion

Join Date: Dec 2008 Posts: 149

Just use try/catch.

Code:

while True:
    try:
        ip = input("Insert (for example: 'ABz a' or 'HNz b'): ")
        random_choice_from_string(ip)
    except:
        print("Try again.")

Quote

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