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Old 08-15-2009, 05:13 PM   #16
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Re: Finishing an opponent heads-up: sage, nash and chubukov.

thanks spamz!
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Old 08-15-2009, 05:28 PM   #17
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Re: Finishing an opponent heads-up: sage, nash and chubukov.

great post spamzor, will read it again.
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Old 08-15-2009, 05:34 PM   #18
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Re: Finishing an opponent heads-up: sage, nash and chubukov.

I'll frame it and hang on my wall. good stuff
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Old 08-15-2009, 06:19 PM   #19
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Re: Finishing an opponent heads-up: sage, nash and chubukov.

i think DocDevil Spammy
fwiw
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Old 08-15-2009, 06:41 PM   #20
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Re: Finishing an opponent heads-up: sage, nash and chubukov.

spamz0r!

About calling shoves from the BB, let me offer this reference table I created some time ago (mostly for exploration) with some remarks:



I used the stoxEV app to create six different generic SB shoving ranges (from 'very tight' to 'very loose') and saw what hands from the BB were +EV calls against each one, as stack depth drops from 12 BBs to 3 BBs. So you look up the BB hand that interests you on the grid, and then check inside its box to see what shoving ranges (denoted by shape) it can make a +EV call against at various maximum stack depths (denoted by color.)

The generic sample SB shoving ranges I used are directly taken from the Sklansky-Chubukov rankings. The hands in each shoving range are listed below the grid, along with what top percentage of all SC shoving hands they comprise.

What I want to note is that in reality, especially in the 12 BB to 9 BB range, villains' shoving ranges will often not be balanced. They'll min-raise, not shove, their monsters, or limp with them. They might not shove some of the (to them) weaker looking hands in a certain range. Or they might especially (but not exclusively) shove hands that don't play well post-flop if they make a smaller raise and get flatted, while min-raising with some of those that do.

So take the table with a grain of salt, use it to get a general feel for BB calling ranges as factors like SB shoving looseness and stack depth change. And play around with stoxEV on your own to model specific scenarios of interest.
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Old 08-15-2009, 07:15 PM   #21
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Re: Finishing an opponent heads-up: sage, nash and chubukov.

Great post spam
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Old 08-18-2009, 10:30 AM   #22
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Re: Finishing an opponent heads-up: sage, nash and chubukov.

good post , thanks
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Old 08-18-2009, 10:40 AM   #23
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Re: Finishing an opponent heads-up: sage, nash and chubukov.

I have a question:
In "Theory And Practice", p. 218, Sklansky gives the following definition of the Sklansky-Chubokov-number:

If you have a face-up hand and a $1 blind, and your sole opponent has a $2 blind, how big does your stack have to be (in dollars, not counting your $1 blind) such that it would be better to fold rather than move in, assuming your opponent calls or folds perfectly.

Doesnt this mean that you have to halve the S-C-number to get the critical stacksize in BB?
For example: K3s has S-C-number 28 (roughly). According to spamz you can openshove +ev with 28 BB or less. According to TAP you can openshove +ev with $28 if the BB is $2, meaning 14 BB.

What do i misunderstand in the definition above?
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Old 08-18-2009, 11:57 AM   #24
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Re: Finishing an opponent heads-up: sage, nash and chubukov.

Bumpity bump for gooood POST ty spamz0r
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Old 08-19-2009, 03:22 AM   #25
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Re: Finishing an opponent heads-up: sage, nash and chubukov.

Quote:
Originally Posted by BeXXs View Post
I have a question:
In "Theory And Practice", p. 218, Sklansky gives the following definition of the Sklansky-Chubokov-number:

If you have a face-up hand and a $1 blind, and your sole opponent has a $2 blind, how big does your stack have to be (in dollars, not counting your $1 blind) such that it would be better to fold rather than move in, assuming your opponent calls or folds perfectly.

Doesnt this mean that you have to halve the S-C-number to get the critical stacksize in BB?
For example: K3s has S-C-number 28 (roughly). According to spamz you can openshove +ev with 28 BB or less. According to TAP you can openshove +ev with $28 if the BB is $2, meaning 14 BB.

What do i misunderstand in the definition above?

Bump the question. I thought as well that S-C-number it's max stack in $ you can push effectively in 1$/2$ game.

Very good read article though.
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Old 08-19-2009, 11:41 AM   #26
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Re: Finishing an opponent heads-up: sage, nash and chubukov.

bump for prosperity.
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Old 08-19-2009, 12:01 PM   #27
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Re: Finishing an opponent heads-up: sage, nash and chubukov.

Quote:
Originally Posted by BeXXs View Post
I have a question:
In "Theory And Practice", p. 218, Sklansky gives the following definition of the Sklansky-Chubokov-number:

If you have a face-up hand and a $1 blind, and your sole opponent has a $2 blind, how big does your stack have to be (in dollars, not counting your $1 blind) such that it would be better to fold rather than move in, assuming your opponent calls or folds perfectly.

Doesnt this mean that you have to halve the S-C-number to get the critical stacksize in BB?
For example: K3s has S-C-number 28 (roughly). According to spamz you can openshove +ev with 28 BB or less. According to TAP you can openshove +ev with $28 if the BB is $2, meaning 14 BB.

What do i misunderstand in the definition above?
wow sick, hold on i'll do some math if this is true OBV has to be changed ASAP because i don't want people to implement huge ev- spots in their game =/
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Old 08-19-2009, 12:26 PM   #28
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Re: Finishing an opponent heads-up: sage, nash and chubukov.

we've been TARPED no wonder I'm on an endless downswing

p.s. can mods please sticky this thread once all the math/errors have been double-checked/fixed, so that we can just refer beginners to it instead of answering the same questions over and over?
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Old 08-19-2009, 12:44 PM   #29
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Re: Finishing an opponent heads-up: sage, nash and chubukov.

really weird, can some people check this with me?

suppose we have KK and openshove, blinds 0.50/1.00; villain will call with KK+ which is 7 combo's (6 AA and 1 KK); against that range we have 22.618% equity according to pokerstove, there's a total of 50*49/2 other hands (because we have two cards, and there's 2! permutations)

SOOOOOOOOOO villain will fold 1218/1225 times, which will net us 1.5bb's each time
villain will call 7/1225 times, we're going to have 22.618% equity against that range, and let's just call our stack Z here
so we need to see where the breakeven point is, and that is by the formula:

1218/1225 * 1.5 - 7/1225 * 0.22618 * Z = 0
<=> 3654/2450 = 1.58325/1225 * Z
<=> 3654/3.16652 = Z
<=> Z = 1154-ish
wtf?
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Old 08-19-2009, 01:02 PM   #30
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Re: Finishing an opponent heads-up: sage, nash and chubukov.

I think it should be


1218/1225 * 1.5 + 7/1225 * 0.22618 * Z - 7/1225 * 0.77382 * Z= 0

Need to factor in both when you win with your KK and lose. I think?

Edit: Which is 476.59 bb, I believe.

Edit 2: Which I also believe that means the Chubukov numbers are in $, and should be 1/2 of what they are for bb.

Last edited by ICallTooMuch; 08-19-2009 at 01:13 PM.
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