Quote:
Originally Posted by BobC
Re cally's 6-12 example, if the rake is $4, the bbjp drop is $1, and you are in a club where everyone tokes the dealer $1, that's an effective rake of $6. So is the conclusion that a 6-12 with this rake structure unbeatable by even good (not necessarily super-good) players?
My example exvluded tips but included a jackpot.
This is the way the math works, just consider everyone's mistakes as going into the pot, rake gets subtracted, and the pot (even ifnegative) divded equally.
So let's saythere's a game where one player makes 3 BB/hr worth of mistakes and the other 9 make 5 BB/hr. At 6/12 roughly 15 BB/hr comes off the table and then the remaining 33 BB is divided. One player nets +0.3 BB/hr and the other 9 net -1.7 BB/hr. The mathematically astute will recognize that the absolute value of the mistakes don't matter, only the spread between the biggest winner and the average of everyone else.
When I played 6/12, which to be fair was a long time ago, $5/hand came off the table (drop plus tip) at about 35 hands/hr, let's say exactly 15 BB/hr. So assuming I was the biggest winner at +1 BB/hr, my average opponent was making -1.8 BB/hr of mistakes relative to me.
Now as stakes get bigger the average opponent gets better but rake goes down proportionally. So whether a bigger stake is beatable heavily depends on how those two factors balance out.
And I pointed this out in another thread recently but unless you're at high stakes where a fraction of a BB is a lot of money, your winrate depends far more onyour ability to beat "the field" (the middle half of the table skillwise) than how bad "the fish" (the worst player) is.