Does this work with a standard 1 ball cut shot?

Huh?

Excellent question. Great explanation of wtf you're talking about.

ive had using the weight of the balls explained to me a few years back, but i cant remember how its used, or explained.I think i might pertain to "dead balls" or combination that are touching.

So, say there is a dead ball combo straight in, when you apply draw to it seeing as it it hit the weight of 2 balls the reaction of the application of reverse will be greatly increased.

The more balls in a line the more the application the cue ball will "take"

https://www.youtube.com/watch?v=X2HM2smEpE8 i think this shows how using the weight of the cue ball and another object ball to chage the throw angle.

You seem confused. This video is just illustrating a basic "throw" shot.

When 2 balls are frozen and you play them in a combination, the second ball will act opposite to what you'd expect. Watch in the video when he hits the first ball on our left. You'd expect the first ball to cut to our right, and the second to our left. This isn't what happens. Because they are frozen together, both balls stick together a bit, and both the first and second balls move to our right. It has nothing to do with the combined mass of the object balls.

As for the cueball having more action after contact with frozen balls, I have never heard of or observed this, but am not positive that it has no effect on the cueball. I do know that if it has an effect, it is very small and not worth worrying about.

I think what he is getting at about the cue ball reaction is for example lets say you have 2 balls frozen together and lined up straight in to a pocket and the cue ball on that same direct line to the pocket. If you shoot that combo straight in with low English the cue ball will draw more than it would if you were shooting the exact same shot but into only one ball. The weight of the 2 balls frozen makes the cue ball stop dead and the spin can take affect faster. It will certainly draw back a noticeable amount further.

this is what i was thinking but i was also taking about if you hit the first ball in the frozen combo doesnt it use the weight of the ball to throw it?

Yeah, but I think it is pushing the ball or sliding it rather than "throwing" it. If 2 balls are frozen and lined up dead straight at the pocket and you shoot the cue ball into the first ball from a 45* angle from the left, the 2nd ball will be pushed to the right and miss the pocket to the right.

right on