In our home game, we now finish the evening playing Midnight Baseball...for those who don't know how to play the rules are simple:

1. You get dealt a fixed amount of cards, face down...in our game, anywhere from 7-10 depending on number of players. You can't look at your hand.

2. All 3s and 9s are wild (8 wild cards)...if you're dealt a 4, you get an extra card. If extra card is another 4, then you still get another card and so on.

3. Five aces is best hand. Followed by 5 of a kind, royal flush etc like poker. Rarely does 4 of a kind win, fwiw.

4. There is no betting...we just throw a fixed amount into the pot, winner take all. Usually 25-50, sometimes we play multiple rounds.

5. You play in clockwise order, turning over cards to beat previous player. So if some is showing three aces, you need to have at least a better three aces or straight to continue. If you can't, you lose and hand is discarded.

6. THERE IS NO SKILL INVOLVED...PURELY LUCK!

So last night we're playing, and we only have four players left. I deal 9 cards to everyone.

I get no wild cards, player on my right gets 5!

My question is: What are odds of being blanked on wild cards with 9 cards? Or getting 3+?

Thanks...silly minds want to know

Cliffs:
9*4 = 36 cards were dealt.
8 cards from the whole the deck are wild.
One player got 5 of them.
You didn't get any wild cards.
You want to know the probability of that happening.

It's obviously rigged.

Yeah...but I shuffled and dealt too! And we don't even cut in our home game!