So in the movie, it was a heads up hand, and it was the first and only hand that the players played. And it was obviously a cooler hand for dramatic purposes. So I guess my question is what are the odds of this specific situation happening in one hand?
Here's my attempt at the math, could somebody see if it's correct reasoning?
Player A being dealt AA:
4/52 * 3/51 = 1/221
Player B being dealt KK:
4/50 * 3/49 = 6/1225
Flop being AAK:
(1/48 * 1/47 * 2/46) * 6 = 1/8648
Is my flop calculation correct? I'm treating each Ace individually whereas there are two remaining Kings, then multiplying by 6 since it doesn't matter what order the flop comes out.
If those odds are correct, I'd multiply them together for: