Quote:
Originally Posted by Guy Whiz
I allowed for the full house in my answer. How do you count one out to the river? I am giving an example of top set against running cards of a suit.
I am sure someone can play around with an odds calcualtor and put in various situations and come up with different scenarios.
The question is worded oddly? Maybe it should be what is the chance you will win with a back door flush as your only outs?
I count one out, because you have 4,2% chance you make your
backdoor flush as counted DrVan above. And I roughly count 4% for each out (up to 7
outs, then I remeber accurate % for 8, 9, 12 and 15
outs). I dont understand, why Sklansky counts 1,5
outs, but as far as I remember Harrington counts 1 out. Accurately one out (making your hand on turn or river) means 4,2553% which is very very close to your chances making your
backdoor flush.
If you are asking, what is your chances against set, its little less. It depends, if you hold suit of the card on the flop, which gives your opponent set or not. He can have either one or two ways to make his full house if you make a flush. In your case, he has two ways (Qh, 2h), so you actually have 8 not 10 "
backdoor"
outs, so your chances are 8/45 x 7/44 = 2,83%.
I thing you should be aware of these added
outs only in limit games, where they can turn your play from correct folding to correct calling.
Last edited by Kecinpulach; 08-18-2008 at 04:54 AM.