Like everyone else (it seems), I have been playing around with pip counting methods. I came up with a 2-step method that I haven't seen in print. For what it's worth:
(Step 1) Mentally, calculate the number of pips it would take to move each and every checker onto the 1st point in the next quadrant. For example, it would take 5 pips to move the white checker on the 23 point to the 18 point, 4 pips to move the 2 checkers on the 20 point to the 18 point, 2 pips to move the 2 on the 13 point to the 12 point, etc. For those in the home court, add the pips required to bear them off.
In the position above, using this method, the total for white would be 46 pips.
(Step 2) Count the total crossovers. Since you have moved (mentally) everything to the next quadrant, count those in the opponents home court as 3 crossovers, those in the opponents outer court as 2 crossovers, and those in your outer court as 1 crossover. Those in your home court aren't counted because you have already moved them (mentally) off the board. Multiply the crossovers times 6 and add this to white's pip count counted in step 1.
In the position above, there are 17 crossovers for white, for a pip count of 17 x 6 = 102. Add that to the 46 pips in step 1, for a total of 148 pips for white.
Repeat for red. In step one, I get 42 pips. In step 2, I get 19 crossovers for 19 x 6 = 114 pips. Total for red of 114 + 42 = 156 pips
Actually, this method takes about as long as a full count but was given mainly as a prelude to the next method, in order to show the principle.
Same position. This is a pip difference method. It only gives the difference in the player's pip counts. It goes very fast and the numbers dealt with are quite small.
(Step 1) Do exactly as in the 1st method except count only those checkers that don't have a checker of different color opposite them on the board. In other words, count only the excess checkers. In the position given above, only those without an X are counted.
For white, the count is 12. For red, it is 8. The difference is 4. I first do step 1 for both and then memorize the difference. I would remember this as W4.
(Step 2) Count the crossovers the same way as in the full-count method, here again counting only those excess checkers.
For white, there are 4 crossovers and for red there are 6. Red has 2 more than white, for a 2 x 6 = 12 pip difference.
Therefore, Red has a 12 - 4 = 8 higher pip count than white.
Last edited by goldsilverpro; 02-04-2015 at 06:32 PM.