For the six, there seems to be only one possibility: make the outfield point, 23/17. The only other play would be to run one man, 17/11, surrendering outfield control. After running, no matter how the two is played, one checker would be left stranded in White's innner board. Let's reject that.
So, that leaves 23/17 as the best six, and Black need only choose a two. Here, there are two reasonable choices:
- 10/8 - This move gives White 14 shots, but keeps all four points in Black's home board.
- 5/3 - The alternative maximizes safety, at the cost of busting - for the moment - Black's home board. White would have 11 shots.
Breaking the board seems premature. Black should keep his strong inner board as a threat to White's blots in the outfield. If he goes for safety instead, he'll have to forego most of his hitting options on the next turn.
My solution:
23/17, 10/8
For the Record
I am so often wrong that I like to post my record in these messages. It's kind of a truth-in-advertising thing. I have been answering these problems without the use of a bot, and before checking the excellent solutions of others, since Problem 28. Including the 39a tossup, my record at this writing is 54% correct.
19 Correct: 28a, 29, 30, 32, 35, 36, 38, 39a, 39b, 42b, 43, 44, 45, 47, 48a, 48b, 50, 52b, 53.
16 Incorrect: 28b, 31, 33a, 33b, 34, 37, 40a, 40b, 41, 42a, 46, 48c, 49, 51, 52a, 54.